ATP Finals de duplas - 2014

Grupo A

Alexander Peya/Bruno Soares
Lukasz Kubot/Robert Lindstedt
Bob Bryan/Mike Bryan
Jean-Julien Rojer/Horia Tecau

10/11 - 10 horas

Peya/Soares 2 x 1 Rojer/Tecau 6/3, 3/6, 12/10

10/11 - 16 horas 

Bryan/Bryan 0 x 2 Kubot/Lindstedt 6/7, 3/6

12/11 - 10 horas

Bryan/Bryan 2 x 1 Rojer/Tecau 6/7, 6/3, 10/6

12/11 - 16 horas 

Peya/Soares 1 x 2 Kubot/Lindstedt 4/6, 6/3, 6/10

14/11 - 10 horas

Kubot/Lindstedt 2 x 0 Rojer/Tecau 6/4, 7/6

14/11 - 16 horas 

Peya/Soares 0 x 2 Bryan/Bryan 6/7, 6/7

Grupo B

Julien Benneteau/Edouard Roger-Vasselin
Marcel Granollers/Marc Lopez
Ivan Dodig/Marcelo Melo
Daniel Nestor/Nenad Zimonjic

09/11 - 10 horas

Benneteau/Vasselin 0 x 2 Granollers/Lopez 4/6, 4/6

09/11 - 16 horas

Nestor/Zimonjic 0 x 2 Dodig/Melo 3/6, 5/7

11/11 - 10 horas

Benneteau/Vasselin 2 x 1 Nestor/Zimonjic 6/4, 5/7, 10/4

11/11 - 16 horas

Granollers/Lopez 0 x 2 Dodig/Melo 6/7, 6/7

13/11 - 10 horas 

Nestor/Zimonjic 2 x 1 Granollers/Lopez 6/7, 6/3, 11/9

13/11 - 16 horas

Dodig/Melo 1 x 2 Benneteau/Vasselin 6/4, 2/6, 8/10

Semifinal

Dodig/Melo 2 x 1 Kubot/Lindstedt 4/6, 6/4, 10/6
Benneteau /Vasselin 0 x 2 Bryan/Bryan 0/6, 3/6

Final

Dodig/Melo 1 x 2 Bryan/Bryan 7/6, 2/6, 7/10

Bob Bryan/Mike Bryan campeões 

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